If you add any new nodes to the tail of the current linked list, the list will become unsorted, because it does not care what values you are passing, it will simply keep appending the new node at the end of the list. Thus any add operation is O(n) because you will have to sequentially navigate to the end of the list before adding the new node.

Time complexity of remove operation, however varies. If you are removing the head node, the operation takes O(1) time and if you are removing the tail, it takes O(n) time. It really depends on where the node to be deleted is located.

The following source code show you:

- How to represent unsorted linked list
- How to add a node
- How to remove a node

package com.icodejava.blog; /** * @author Kushal Paudyal * www.icodejava.com * Created On - Mar 9, 2014 * Last Modified On - Mar 9, 2014 */ public class LinkedListOperation { public static void main(String args[]) { LinkedListNode linkedList = new LinkedListNode(4).addNode(5).addNode(2).addNode(-5); System.out.println("Final List: " + linkedList +"\n"); // Deleting nodes in an order different from how they were added. linkedList = linkedList.removeNode(5).removeNode(-5).removeNode(2).removeNode(4); System.out.println("After Removal, the list is: " + linkedList); } } @SuppressWarnings({"rawtypes", "unchecked"}) class LinkedListNode { private LinkedListNode next; private Comparable value = null; public LinkedListNode(Comparable value) { // create first node next = null; this.value = value; System.out.println("Adding Node: " + value); } /** * This method removes a node from a linked list. */ public LinkedListNode removeNode(Comparable nodeValue) { System.out.println("Removing Node: " + nodeValue); if (this.value.compareTo(nodeValue) == 0) { // head return this.next; } else { // non head LinkedListNode current = this; LinkedListNode previous = null; while (current.next != null) { if (current.value.compareTo(nodeValue) == 0) { previous.next = current.next; return this; } previous = current; current = current.next; } if (current.value.compareTo(nodeValue) == 0) { // tail previous.next = null; } } return this; } @Override public String toString() { String data = ""; LinkedListNode current = this; do { data += current.value + ","; current = current.next; } while (current != null); return data; } /** * Adds the node at the tail, making it an unsorted linked list. This method * returns a head node. */ public LinkedListNode addNode(Comparable value) { // if first node if (this.next == null) { LinkedListNode node = new LinkedListNode(value); this.next = node; this.next.next = null; } else { LinkedListNode current = this.next; while (current.next != null) { current = current.next; } LinkedListNode node = new LinkedListNode(value); current.next = node; current.next.next = null; } return this; // return head } }

Here is the output of running the above program:

Adding Node: 4 Adding Node: 5 Adding Node: 2 Adding Node: -5 Final List: 4,5,2,-5, Removing Node: 5 Removing Node: -5 Removing Node: 2 Removing Node: 4 After Removal, the list is: null[My Video Promotion]

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